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(2x-2)/(2x+2)x=1
We move all terms to the left:
(2x-2)/(2x+2)x-(1)=0
Domain of the equation: (2x+2)x!=0We multiply all the terms by the denominator
x∈R
(2x-2)-1*(2x+2)x=0
We multiply parentheses
-2x^2+(2x-2)-2x=0
We get rid of parentheses
-2x^2+2x-2x-2=0
We add all the numbers together, and all the variables
-2x^2-2=0
a = -2; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-2)·(-2)
Δ = -16
Delta is less than zero, so there is no solution for the equation
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