8z+28=12

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Solution for 8z+28=12 equation:



8z+28=12
We move all terms to the left:
8z+28-(12)=0
We add all the numbers together, and all the variables
8z+16=0
We move all terms containing z to the left, all other terms to the right
8z=-16
z=-16/8
z=-2

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