(2x-2)+(x+1)+x+(x+1)=(2x+9)+(x+1)+(x+8)+x

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Solution for (2x-2)+(x+1)+x+(x+1)=(2x+9)+(x+1)+(x+8)+x equation:



(2x-2)+(x+1)+x+(x+1)=(2x+9)+(x+1)+(x+8)+x
We move all terms to the left:
(2x-2)+(x+1)+x+(x+1)-((2x+9)+(x+1)+(x+8)+x)=0
We add all the numbers together, and all the variables
x+(2x-2)+(x+1)+(x+1)-((2x+9)+(x+1)+(x+8)+x)=0
We get rid of parentheses
x+2x+x+x-((2x+9)+(x+1)+(x+8)+x)-2+1+1=0
We calculate terms in parentheses: -((2x+9)+(x+1)+(x+8)+x), so:
(2x+9)+(x+1)+(x+8)+x
We add all the numbers together, and all the variables
x+(2x+9)+(x+1)+(x+8)
We get rid of parentheses
x+2x+x+x+9+1+8
We add all the numbers together, and all the variables
5x+18
Back to the equation:
-(5x+18)
We add all the numbers together, and all the variables
5x-(5x+18)=0
We get rid of parentheses
5x-5x-18=0
We add all the numbers together, and all the variables
-18!=0
There is no solution for this equation

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