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5/(x+3)=4/(x-3)
We move all terms to the left:
5/(x+3)-(4/(x-3))=0
Domain of the equation: (x+3)!=0
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
Domain of the equation: (x-3))!=0We calculate fractions
x∈R
5x/((x+3)*(x-3)))+(-(4*(x+3))/((x+3)*(x-3)))=0
We calculate terms in parentheses: -(4*(x+3))/((x+3)*(x-3))), so:We add all the numbers together, and all the variables
4*(x+3))/((x+3)*(x-3))
We multiply all the terms by the denominator
4*(x+3))
We multiply parentheses
4x+
We add all the numbers together, and all the variables
4x
Back to the equation:
-(4x)
-4x+5x/((x+3)*(x-3)))+(=0
We multiply all the terms by the denominator
-4x*((x+3)*(x-3)))+(+5x=0
We add all the numbers together, and all the variables
5x-4x*((x+3)*(x-3)))+(=0
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