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(2x-15)x=97.5
We move all terms to the left:
(2x-15)x-(97.5)=0
We add all the numbers together, and all the variables
(2x-15)x-97.5=0
We multiply parentheses
2x^2-15x-97.5=0
a = 2; b = -15; c = -97.5;
Δ = b2-4ac
Δ = -152-4·2·(-97.5)
Δ = 1005
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1005}}{2*2}=\frac{15-\sqrt{1005}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1005}}{2*2}=\frac{15+\sqrt{1005}}{4} $
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