(2x-15)/6=(6x-30)/8

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Solution for (2x-15)/6=(6x-30)/8 equation: 



(2x-15)/6=(6x-30)/8

We move all terms to the left:

(2x-15)/6-((6x-30)/8)=0

We calculate fractions


2x/()+(-((6x-30)*6)/()=0



We calculate terms in parentheses: +(-((6x-30)*6)/(), so:

-((6x-30)*6)/(

We multiply all the terms by the denominator


-((6x-30)*6)



We calculate terms in parentheses: -((6x-30)*6), so:

(6x-30)*6

We multiply parentheses

36x-180

Back to the equation:

-(36x-180)



We get rid of parentheses

-36x+180

Back to the equation:

+(-36x+180)



We get rid of parentheses

2x/()-36x+180=0

We multiply all the terms by the denominator


2x-36x*()+180*()=0

We add all the numbers together, and all the variables

2x-36x*()=0

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