4(2x+3)3=7+(3x-6)

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Solution for 4(2x+3)3=7+(3x-6) equation: 



4(2x+3)3=7+(3x-6)

We move all terms to the left:

4(2x+3)3-(7+(3x-6))=0

We multiply parentheses

24x-(7+(3x-6))+36=0



We calculate terms in parentheses: -(7+(3x-6)), so:

7+(3x-6)

determiningTheFunctionDomain
(3x-6)+7

We get rid of parentheses

3x-6+7

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

24x-3x-1+36=0

We add all the numbers together, and all the variables

21x+35=0

We move all terms containing x to the left, all other terms to the right

21x=-35

x=-35/21

x=-1+2/3

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