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(2x-10)(3x-18)=0
We multiply parentheses ..
(+6x^2-36x-30x+180)=0
We get rid of parentheses
6x^2-36x-30x+180=0
We add all the numbers together, and all the variables
6x^2-66x+180=0
a = 6; b = -66; c = +180;
Δ = b2-4ac
Δ = -662-4·6·180
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-6}{2*6}=\frac{60}{12} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+6}{2*6}=\frac{72}{12} =6 $
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