(x+2)(4x+8)=0

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Solution for (x+2)(4x+8)=0 equation: 



(x+2)(4x+8)=0

We multiply parentheses ..

(+4x^2+8x+8x+16)=0

We get rid of parentheses

4x^2+8x+8x+16=0

We add all the numbers together, and all the variables

4x^2+16x+16=0

a = 4; b = 16; c = +16;
Δ = b2-4ac
Δ = 162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{8}=-2$

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