(2x-1)/9=(x+3)/2

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Solution for (2x-1)/9=(x+3)/2 equation: 



(2x-1)/9=(x+3)/2

We move all terms to the left:

(2x-1)/9-((x+3)/2)=0

We calculate fractions


2x/()+(-((x+3)*9)/()=0



We calculate terms in parentheses: +(-((x+3)*9)/(), so:

-((x+3)*9)/(

We multiply all the terms by the denominator


-((x+3)*9)



We calculate terms in parentheses: -((x+3)*9), so:

(x+3)*9

We multiply parentheses

9x+27

Back to the equation:

-(9x+27)



We get rid of parentheses

-9x-27

Back to the equation:

+(-9x-27)



We get rid of parentheses

2x/()-9x-27=0

We multiply all the terms by the denominator


2x-9x*()-27*()=0

We add all the numbers together, and all the variables

2x-9x*()=0

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