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(2x-1)/3+3=x
We move all terms to the left:
(2x-1)/3+3-(x)=0
We add all the numbers together, and all the variables
-1x+(2x-1)/3+3=0
We multiply all the terms by the denominator
-1x*3+(2x-1)+3*3=0
We add all the numbers together, and all the variables
-1x*3+(2x-1)+9=0
Wy multiply elements
-3x+(2x-1)+9=0
We get rid of parentheses
-3x+2x-1+9=0
We add all the numbers together, and all the variables
-1x+8=0
We move all terms containing x to the left, all other terms to the right
-x=-8
x=-8/-1
x=+8
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