8*(6t-5)-(1-4t)=8*(t/2)

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Solution for 8*(6t-5)-(1-4t)=8*(t/2) equation:



8(6t-5)-(1-4t)=8(t/2)
We move all terms to the left:
8(6t-5)-(1-4t)-(8(t/2))=0
We add all the numbers together, and all the variables
8(6t-5)-(-4t+1)-(8(+t/2))=0
We multiply parentheses
48t-(-4t+1)-(8(+t/2))-40=0
We get rid of parentheses
48t+4t-(8(+t/2))-1-40=0
We multiply all the terms by the denominator
48t*2))+4t*2))-(8(+t-1*2))-40*2))=0
We add all the numbers together, and all the variables
48t*2))+4t*2))-(8(t-2))-40*2))=0
Wy multiply elements
384t^4=0
We do not support etpression: t^4

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