(2x-1)+(3x-2)+(7x+3)=180

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Solution for (2x-1)+(3x-2)+(7x+3)=180 equation: 



(2x-1)+(3x-2)+(7x+3)=180

We move all terms to the left:

(2x-1)+(3x-2)+(7x+3)-(180)=0

We get rid of parentheses

2x+3x+7x-1-2+3-180=0

We add all the numbers together, and all the variables

12x-180=0

We move all terms containing x to the left, all other terms to the right

12x=180

x=180/12

x=15

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