-3(4y+4)-3y=3(y-1)-6

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Solution for -3(4y+4)-3y=3(y-1)-6 equation: 



-3(4y+4)-3y=3(y-1)-6

We move all terms to the left:

-3(4y+4)-3y-(3(y-1)-6)=0

We add all the numbers together, and all the variables

-3y-3(4y+4)-(3(y-1)-6)=0

We multiply parentheses

-3y-12y-(3(y-1)-6)-12=0



We calculate terms in parentheses: -(3(y-1)-6), so:

3(y-1)-6

We multiply parentheses

3y-3-6

We add all the numbers together, and all the variables

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

-15y-(3y-9)-12=0

We get rid of parentheses

-15y-3y+9-12=0

We add all the numbers together, and all the variables

-18y-3=0

We move all terms containing y to the left, all other terms to the right

-18y=3

y=3/-18

y=-1/6

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