(2x-1)+(2x-5)=(10x-10)

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Solution for (2x-1)+(2x-5)=(10x-10) equation: 



(2x-1)+(2x-5)=(10x-10)

We move all terms to the left:

(2x-1)+(2x-5)-((10x-10))=0

We get rid of parentheses

2x+2x-((10x-10))-1-5=0



We calculate terms in parentheses: -((10x-10)), so:

(10x-10)

We get rid of parentheses

10x-10

Back to the equation:

-(10x-10)



We add all the numbers together, and all the variables

4x-(10x-10)-6=0

We get rid of parentheses

4x-10x+10-6=0

We add all the numbers together, and all the variables

-6x+4=0

We move all terms containing x to the left, all other terms to the right

-6x=-4

x=-4/-6

x=2/3

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