(10x-10)+(2x-5)=(2x-1)

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Solution for (10x-10)+(2x-5)=(2x-1) equation: 



(10x-10)+(2x-5)=(2x-1)

We move all terms to the left:

(10x-10)+(2x-5)-((2x-1))=0

We get rid of parentheses

10x+2x-((2x-1))-10-5=0



We calculate terms in parentheses: -((2x-1)), so:

(2x-1)

We get rid of parentheses

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

12x-(2x-1)-15=0

We get rid of parentheses

12x-2x+1-15=0

We add all the numbers together, and all the variables

10x-14=0

We move all terms containing x to the left, all other terms to the right

10x=14

x=14/10

x=1+2/5

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