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(2x-1)(x-6)=-2(x-6)
We move all terms to the left:
(2x-1)(x-6)-(-2(x-6))=0
We multiply parentheses ..
(+2x^2-12x-1x+6)-(-2(x-6))=0
We calculate terms in parentheses: -(-2(x-6)), so:We get rid of parentheses
-2(x-6)
We multiply parentheses
-2x+12
Back to the equation:
-(-2x+12)
2x^2-12x-1x+2x+6-12=0
We add all the numbers together, and all the variables
2x^2-11x-6=0
a = 2; b = -11; c = -6;
Δ = b2-4ac
Δ = -112-4·2·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-13}{2*2}=\frac{-2}{4} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+13}{2*2}=\frac{24}{4} =6 $
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