(x-5)+x+(x+1)+29=4x

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Solution for (x-5)+x+(x+1)+29=4x equation: 



(x-5)+x+(x+1)+29=4x

We move all terms to the left:

(x-5)+x+(x+1)+29-(4x)=0

We add all the numbers together, and all the variables

-3x+(x-5)+(x+1)+29=0

We get rid of parentheses

-3x+x+x-5+1+29=0

We add all the numbers together, and all the variables

-1x+25=0

We move all terms containing x to the left, all other terms to the right

-x=-25

x=-25/-1

x=+25

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