(2x+9)(3x+1)=

Solution for (2x+9)(3x+1)= equation:

(2x+9)(3x+1)=

We move all terms to the left:

(2x+9)(3x+1)-()=0

We add all the numbers together, and all the variables

(2x+9)(3x+1)=0

We multiply parentheses ..

(+6x^2+2x+27x+9)=0

We get rid of parentheses

6x^2+2x+27x+9=0

We add all the numbers together, and all the variables

6x^2+29x+9=0

a = 6; b = 29; c = +9;
Δ = b2-4ac
Δ = 292-4·6·9
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-25}{2*6}=\frac{-54}{12}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+25}{2*6}=\frac{-4}{12}
=-1/3
$