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(2x+8)(-x+5)=0
We add all the numbers together, and all the variables
(2x+8)(-1x+5)=0
We multiply parentheses ..
(-2x^2+10x-8x+40)=0
We get rid of parentheses
-2x^2+10x-8x+40=0
We add all the numbers together, and all the variables
-2x^2+2x+40=0
a = -2; b = 2; c = +40;
Δ = b2-4ac
Δ = 22-4·(-2)·40
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*-2}=\frac{16}{-4} =-4 $
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