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(2x+7)(7x+4)=0
We multiply parentheses ..
(+14x^2+8x+49x+28)=0
We get rid of parentheses
14x^2+8x+49x+28=0
We add all the numbers together, and all the variables
14x^2+57x+28=0
a = 14; b = 57; c = +28;
Δ = b2-4ac
Δ = 572-4·14·28
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-41}{2*14}=\frac{-98}{28} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+41}{2*14}=\frac{-16}{28} =-4/7 $
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