2x-4=4+8(x-1/2)

Solution for 2x-4=4+8(x-1/2) equation:

2x-4=4+8(x-1/2)

We move all terms to the left:

2x-4-(4+8(x-1/2))=0

We add all the numbers together, and all the variables

2x-(4+8(+x-1/2))-4=0

We multiply all the terms by the denominator


2x*2))-(4+8(+x-1-4*2))=0

We add all the numbers together, and all the variables

2x*2))-(4+8(x-9))=0

We add all the numbers together, and all the variables

2x*2))-(4+8(x=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$