(2x+65)=40+(9x-45)

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Solution for (2x+65)=40+(9x-45) equation: 



(2x+65)=40+(9x-45)

We move all terms to the left:

(2x+65)-(40+(9x-45))=0

We get rid of parentheses

2x-(40+(9x-45))+65=0



We calculate terms in parentheses: -(40+(9x-45)), so:

40+(9x-45)

determiningTheFunctionDomain
(9x-45)+40

We get rid of parentheses

9x-45+40

We add all the numbers together, and all the variables

9x-5

Back to the equation:

-(9x-5)



We get rid of parentheses

2x-9x+5+65=0

We add all the numbers together, and all the variables

-7x+70=0

We move all terms containing x to the left, all other terms to the right

-7x=-70

x=-70/-7

x=+10

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