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2y+2=y+2(y-5)
We move all terms to the left:
2y+2-(y+2(y-5))=0
We calculate terms in parentheses: -(y+2(y-5)), so:We get rid of parentheses
y+2(y-5)
We multiply parentheses
y+2y-10
We add all the numbers together, and all the variables
3y-10
Back to the equation:
-(3y-10)
2y-3y+10+2=0
We add all the numbers together, and all the variables
-1y+12=0
We move all terms containing y to the left, all other terms to the right
-y=-12
y=-12/-1
y=+12
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