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(2x+52)(2x-46)=0
We multiply parentheses ..
(+4x^2-92x+104x-2392)=0
We get rid of parentheses
4x^2-92x+104x-2392=0
We add all the numbers together, and all the variables
4x^2+12x-2392=0
a = 4; b = 12; c = -2392;
Δ = b2-4ac
Δ = 122-4·4·(-2392)
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38416}=196$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-196}{2*4}=\frac{-208}{8} =-26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+196}{2*4}=\frac{184}{8} =23 $
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