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(2x+5)/(3x+1)=3/11
We move all terms to the left:
(2x+5)/(3x+1)-(3/11)=0
Domain of the equation: (3x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x!=-1
x!=-1/3
x!=-1/3
x∈R
(2x+5)/(3x+1)-(+3/11)=0
We get rid of parentheses
(2x+5)/(3x+1)-3/11=0
We calculate fractions
(22x+55)/(33x+11)+(-9x-3)/(33x+11)=0
We multiply all the terms by the denominator
(22x+55)+(-9x-3)=0
We get rid of parentheses
22x-9x+55-3=0
We add all the numbers together, and all the variables
13x+52=0
We move all terms containing x to the left, all other terms to the right
13x=-52
x=-52/13
x=-4
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