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1x+3x+(3x-10)+((3x-10)/2)=495
We move all terms to the left:
1x+3x+(3x-10)+((3x-10)/2)-(495)=0
We add all the numbers together, and all the variables
4x+(3x-10)+((3x-10)/2)-495=0
We get rid of parentheses
4x+3x+((3x-10)/2)-10-495=0
We multiply all the terms by the denominator
4x*2)+3x*2)+((3x-10)-10*2)-495*2)=0
We add all the numbers together, and all the variables
4x*2)+3x*2)+((3x=0
Wy multiply elements
16x^3=0
We do not support expression: x^3
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