(2x+5)+(x-7)+21+68=150

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Solution for (2x+5)+(x-7)+21+68=150 equation: 



(2x+5)+(x-7)+21+68=150

We move all terms to the left:

(2x+5)+(x-7)+21+68-(150)=0

We add all the numbers together, and all the variables

(2x+5)+(x-7)-61=0

We get rid of parentheses

2x+x+5-7-61=0

We add all the numbers together, and all the variables

3x-63=0

We move all terms containing x to the left, all other terms to the right

3x=63

x=63/3

x=21

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