4(t-6)=3(t-1)

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Solution for 4(t-6)=3(t-1) equation: 



4(t-6)=3(t-1)

We move all terms to the left:

4(t-6)-(3(t-1))=0

We multiply parentheses

4t-(3(t-1))-24=0



We calculate terms in parentheses: -(3(t-1)), so:

3(t-1)

We multiply parentheses

3t-3

Back to the equation:

-(3t-3)



We get rid of parentheses

4t-3t+3-24=0

We add all the numbers together, and all the variables

t-21=0

We move all terms containing t to the left, all other terms to the right

t=21

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