(2x+5)+(x+3)+(x+8)=36

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Solution for (2x+5)+(x+3)+(x+8)=36 equation: 



(2x+5)+(x+3)+(x+8)=36

We move all terms to the left:

(2x+5)+(x+3)+(x+8)-(36)=0

We get rid of parentheses

2x+x+x+5+3+8-36=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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