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(2x+5)+(2x)+(x+30)+(x)=479
We move all terms to the left:
(2x+5)+(2x)+(x+30)+(x)-(479)=0
We add all the numbers together, and all the variables
3x+(2x+5)+(x+30)-479=0
We get rid of parentheses
3x+2x+x+5+30-479=0
We add all the numbers together, and all the variables
6x-444=0
We move all terms containing x to the left, all other terms to the right
6x=444
x=444/6
x=74
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