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3(x-5)-2=(x-11)
We move all terms to the left:
3(x-5)-2-((x-11))=0
We multiply parentheses
3x-((x-11))-15-2=0
We calculate terms in parentheses: -((x-11)), so:We add all the numbers together, and all the variables
(x-11)
We get rid of parentheses
x-11
Back to the equation:
-(x-11)
3x-(x-11)-17=0
We get rid of parentheses
3x-x+11-17=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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