(2x+40)+(3x-13)=116

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Solution for (2x+40)+(3x-13)=116 equation: 



(2x+40)+(3x-13)=116

We move all terms to the left:

(2x+40)+(3x-13)-(116)=0

We get rid of parentheses

2x+3x+40-13-116=0

We add all the numbers together, and all the variables

5x-89=0

We move all terms containing x to the left, all other terms to the right

5x=89

x=89/5

x=17+4/5

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