(2x+4)/4=(3x+1)/5

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Solution for (2x+4)/4=(3x+1)/5 equation:



(2x+4)/4=(3x+1)/5
We move all terms to the left:
(2x+4)/4-((3x+1)/5)=0
We calculate fractions
2x/()+(-((3x+1)*4)/()=0
We calculate terms in parentheses: +(-((3x+1)*4)/(), so:
-((3x+1)*4)/(
We multiply all the terms by the denominator
-((3x+1)*4)
We calculate terms in parentheses: -((3x+1)*4), so:
(3x+1)*4
We multiply parentheses
12x+4
Back to the equation:
-(12x+4)
We get rid of parentheses
-12x-4
Back to the equation:
+(-12x-4)
We get rid of parentheses
2x/()-12x-4=0
We multiply all the terms by the denominator
2x-12x*()-4*()=0
We add all the numbers together, and all the variables
2x-12x*()=0

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