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(2x+4)(x+7)=2
We move all terms to the left:
(2x+4)(x+7)-(2)=0
We multiply parentheses ..
(+2x^2+14x+4x+28)-2=0
We get rid of parentheses
2x^2+14x+4x+28-2=0
We add all the numbers together, and all the variables
2x^2+18x+26=0
a = 2; b = 18; c = +26;
Δ = b2-4ac
Δ = 182-4·2·26
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{29}}{2*2}=\frac{-18-2\sqrt{29}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{29}}{2*2}=\frac{-18+2\sqrt{29}}{4} $
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