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-3(3v-2)+7v=7+2(2v-5)
We move all terms to the left:
-3(3v-2)+7v-(7+2(2v-5))=0
We add all the numbers together, and all the variables
7v-3(3v-2)-(7+2(2v-5))=0
We multiply parentheses
7v-9v-(7+2(2v-5))+6=0
We calculate terms in parentheses: -(7+2(2v-5)), so:We add all the numbers together, and all the variables
7+2(2v-5)
determiningTheFunctionDomain 2(2v-5)+7
We multiply parentheses
4v-10+7
We add all the numbers together, and all the variables
4v-3
Back to the equation:
-(4v-3)
-2v-(4v-3)+6=0
We get rid of parentheses
-2v-4v+3+6=0
We add all the numbers together, and all the variables
-6v+9=0
We move all terms containing v to the left, all other terms to the right
-6v=-9
v=-9/-6
v=1+1/2
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