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(2x+4)(x+5)=90
We move all terms to the left:
(2x+4)(x+5)-(90)=0
We multiply parentheses ..
(+2x^2+10x+4x+20)-90=0
We get rid of parentheses
2x^2+10x+4x+20-90=0
We add all the numbers together, and all the variables
2x^2+14x-70=0
a = 2; b = 14; c = -70;
Δ = b2-4ac
Δ = 142-4·2·(-70)
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6\sqrt{21}}{2*2}=\frac{-14-6\sqrt{21}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6\sqrt{21}}{2*2}=\frac{-14+6\sqrt{21}}{4} $
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