(2x+4)(16x-8)=0

Solution for (2x+4)(16x-8)=0 equation:

(2x+4)(16x-8)=0

We multiply parentheses ..

(+32x^2-16x+64x-32)=0

We get rid of parentheses

32x^2-16x+64x-32=0

We add all the numbers together, and all the variables

32x^2+48x-32=0

a = 32; b = 48; c = -32;
Δ = b2-4ac
Δ = 482-4·32·(-32)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-80}{2*32}=\frac{-128}{64}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+80}{2*32}=\frac{32}{64}
=1/2
$