(5w+2)(5+w)=0

Solution for (5w+2)(5+w)=0 equation:

(5w+2)(5+w)=0

We add all the numbers together, and all the variables

(5w+2)(w+5)=0

We multiply parentheses ..

(+5w^2+25w+2w+10)=0

We get rid of parentheses

5w^2+25w+2w+10=0

We add all the numbers together, and all the variables

5w^2+27w+10=0

a = 5; b = 27; c = +10;
Δ = b2-4ac
Δ = 272-4·5·10
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-23}{2*5}=\frac{-50}{10}
=-5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+23}{2*5}=\frac{-4}{10}
=-2/5
$