(2x+32)=(3x+23)

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Solution for (2x+32)=(3x+23) equation: 



(2x+32)=(3x+23)

We move all terms to the left:

(2x+32)-((3x+23))=0

We get rid of parentheses

2x-((3x+23))+32=0



We calculate terms in parentheses: -((3x+23)), so:

(3x+23)

We get rid of parentheses

3x+23

Back to the equation:

-(3x+23)



We get rid of parentheses

2x-3x-23+32=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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