(2x+30=x,x)

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Solution for (2x+30=x,x) equation: 



(2x+30=x.x)

We move all terms to the left:

(2x+30-(x.x))=0

We add all the numbers together, and all the variables

(2x+30-(+x.x))=0



We calculate terms in parentheses: +(2x+30-(+x.x)), so:

2x+30-(+x.x)

determiningTheFunctionDomain
2x-(+x.x)+30

We get rid of parentheses

2x-x.x+30

Back to the equation:

+(2x-x.x+30)



We get rid of parentheses

2x-x.x+30=0

We move all terms containing x to the left, all other terms to the right

2x-x.x=-30

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