2x/3-x/6=-(3/4)

Solution for 2x/3-x/6=-(3/4) equation:

2x/3-x/6=-(3/4)

We move all terms to the left:

2x/3-x/6-(-(3/4))=0

We add all the numbers together, and all the variables

2x/3-x/6-(-(+3/4))=0

We calculate fractions


(-48x^2)/()+192x^2/()+()/()=0

We add all the numbers together, and all the variables

(-48x^2)/()+192x^2/()+1=0

We multiply all the terms by the denominator


(-48x^2)+192x^2+1*()=0

We add all the numbers together, and all the variables

192x^2+(-48x^2)=0

We get rid of parentheses

192x^2-48x^2=0

We add all the numbers together, and all the variables

144x^2=0

a = 144; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·144·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{288}=0$