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(2x+3)=(2x-5)
We move all terms to the left:
(2x+3)-((2x-5))=0
We get rid of parentheses
2x-((2x-5))+3=0
We calculate terms in parentheses: -((2x-5)), so:We get rid of parentheses
(2x-5)
We get rid of parentheses
2x-5
Back to the equation:
-(2x-5)
2x-2x+5+3=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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