(2x+3)2+(x+4)2=10

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Solution for (2x+3)2+(x+4)2=10 equation: 



(2x+3)2+(x+4)2=10

We move all terms to the left:

(2x+3)2+(x+4)2-(10)=0

We multiply parentheses

4x+2x+6+8-10=0

We add all the numbers together, and all the variables

6x+4=0

We move all terms containing x to the left, all other terms to the right

6x=-4

x=-4/6

x=-2/3

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