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x(13x-14)=72
We move all terms to the left:
x(13x-14)-(72)=0
We multiply parentheses
13x^2-14x-72=0
a = 13; b = -14; c = -72;
Δ = b2-4ac
Δ = -142-4·13·(-72)
Δ = 3940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3940}=\sqrt{4*985}=\sqrt{4}*\sqrt{985}=2\sqrt{985}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{985}}{2*13}=\frac{14-2\sqrt{985}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{985}}{2*13}=\frac{14+2\sqrt{985}}{26} $
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