(2x+3)+(x+2)+(2x+3)+(x+2)=46

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Solution for (2x+3)+(x+2)+(2x+3)+(x+2)=46 equation: 



(2x+3)+(x+2)+(2x+3)+(x+2)=46

We move all terms to the left:

(2x+3)+(x+2)+(2x+3)+(x+2)-(46)=0

We get rid of parentheses

2x+x+2x+x+3+2+3+2-46=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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