3y+1=5(y-3)

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Solution for 3y+1=5(y-3) equation: 



3y+1=5(y-3)

We move all terms to the left:

3y+1-(5(y-3))=0



We calculate terms in parentheses: -(5(y-3)), so:

5(y-3)

We multiply parentheses

5y-15

Back to the equation:

-(5y-15)



We get rid of parentheses

3y-5y+15+1=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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