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(2x+3)(7x+5)=0
We multiply parentheses ..
(+14x^2+10x+21x+15)=0
We get rid of parentheses
14x^2+10x+21x+15=0
We add all the numbers together, and all the variables
14x^2+31x+15=0
a = 14; b = 31; c = +15;
Δ = b2-4ac
Δ = 312-4·14·15
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-11}{2*14}=\frac{-42}{28} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+11}{2*14}=\frac{-20}{28} =-5/7 $
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