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(2x+3)/(4+x)=5
We move all terms to the left:
(2x+3)/(4+x)-(5)=0
Domain of the equation: (4+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-4
x∈R
(2x+3)/(x+4)-5=0
We multiply all the terms by the denominator
(2x+3)-5*(x+4)=0
We multiply parentheses
(2x+3)-5x-20=0
We get rid of parentheses
2x-5x+3-20=0
We add all the numbers together, and all the variables
-3x-17=0
We move all terms containing x to the left, all other terms to the right
-3x=17
x=17/-3
x=-5+2/3
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