(2x+25)+(3x-6)=(x+11)

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Solution for (2x+25)+(3x-6)=(x+11) equation: 



(2x+25)+(3x-6)=(x+11)

We move all terms to the left:

(2x+25)+(3x-6)-((x+11))=0

We get rid of parentheses

2x+3x-((x+11))+25-6=0



We calculate terms in parentheses: -((x+11)), so:

(x+11)

We get rid of parentheses

x+11

Back to the equation:

-(x+11)



We add all the numbers together, and all the variables

5x-(x+11)+19=0

We get rid of parentheses

5x-x-11+19=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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